Quick Ball and Dusk Ball
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Quick Ball and Dusk Ball

Combining Quick Ball with Dusk Ball in a deck isn't a good idea.
Why?
Think of the ratio - Quick Ball works best when numbers of pokemon are low, because it pretty much guarantees a pokemon you need (Example: Speedrill deck.)
If your pokemon are low, there will be more times when you draw 7 and get no pokemon. Replace with pokeball, or evoluter I think.
The only exception to this rule would be Dan's unown deck, which contains unown and most of the time it doesn't matter what unown he gets.

Emz- Admin
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Re: Quick Ball and Dusk Ball
lol u reposted it???
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Re: Quick Ball and Dusk Ball
J 4 M £ Z wrote:lol u reposted it???
Yes.

Emz- Admin
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Re: Quick Ball and Dusk Ball
lol kk
_________________
...J.4.M.£.Z...
A.K.A. the worlds best pop colector
SPEEDRILL OWNZ!!
my phone number: dont hesitate to call but no pranks: 07847840806
add me on runescape:i r0k1z i
add my msn: JAMESSWILLIAMS13@HOTMAIL.COM
check out my myspace: myspace.com/__j4m3z__
creating cards for free...just tell me what yu want and il make it.
I am the posting Champion!!

J 4 M £ Z- Posts: 260
Join date: 2008-07-10
Age: 16
Location: str@tf0rd, £ast l0nd0n

Re: Quick Ball and Dusk Ball
Thought I'd back Emz up with a little bit of Mathhammer. This isn't totally accurate, as it assumes you're seraching from the full 60-card deck, each of which is unknown, but if I wanted to include every possible variable, I'd get lost and muck it up.
Disclaimer: I'm not a total Maths whizz, but I these should be right. Anyone with a superior knowledge, feel free to correct me.
How to work out the odds of getting a pokemon with Dusk Ball
[no. of Pokemon in deck] * 7/60 = [average number of pokemon drawn]
We simplify this to: [no.P]*0.1167=[ave. drawn]
re-writing this to make it more useful, we get: [ave. drawn]/0.1167=[no.P]
To get, on average, at least 1 pokemon on average each time you use Dusk Ball, you need [no.P] = [ave.drawn]/0.1167=1/0.1167=8.57... So, at least 9 pokemon in the deck to mean you draw on average 1 pokemon each time you use Dusk Ball.
However, this would mean you get 1 pokémon roughly half the time, but roughly a quarter of the time you'd get more than that (good, choice.) but roughly a quarter of the time, you'd get none (bad.). I'd say that, with this number of pokemon, you'd be better off with Quick Ball, as on average, you have the same amount of control over which to choose (ie, none), but you have the certainty of getting a pokemon.
So, I think that to make it more useful than Quick Ball, you want to get on average, 2 pokemon a time. This gives you choice 75% of the time, and a much smaller chance of getting nothing.
So, to get at least 2 pokemon on average each time you need 2/0.1167=17.14... so at least 17.
So, in my opinion, if you have less than 17 pokemon in your deck, quick ball is as useful as dusk Ball.
But of course, that depends on what, in your opinion is the number of pokemon you need to draw, on average, each time, to make Dusk Ball worth more than Quick Ball.
More detailed Mathhammer
really, it should be:
[average number of pokemon drawn] = [No. of Pokemon in deck (not in play, in hand, in discard or in prizes)] * 7/[No. of cards in deck (not in play, in hand, in discard or in prizes)]
But there are so many possibilities there that it would take forever to write them up. You cna do a couple yourselves if you think it'll be useful.
Disclaimer: I'm not a total Maths whizz, but I these should be right. Anyone with a superior knowledge, feel free to correct me.
How to work out the odds of getting a pokemon with Dusk Ball
[no. of Pokemon in deck] * 7/60 = [average number of pokemon drawn]
We simplify this to: [no.P]*0.1167=[ave. drawn]
re-writing this to make it more useful, we get: [ave. drawn]/0.1167=[no.P]
To get, on average, at least 1 pokemon on average each time you use Dusk Ball, you need [no.P] = [ave.drawn]/0.1167=1/0.1167=8.57... So, at least 9 pokemon in the deck to mean you draw on average 1 pokemon each time you use Dusk Ball.
However, this would mean you get 1 pokémon roughly half the time, but roughly a quarter of the time you'd get more than that (good, choice.) but roughly a quarter of the time, you'd get none (bad.). I'd say that, with this number of pokemon, you'd be better off with Quick Ball, as on average, you have the same amount of control over which to choose (ie, none), but you have the certainty of getting a pokemon.
So, I think that to make it more useful than Quick Ball, you want to get on average, 2 pokemon a time. This gives you choice 75% of the time, and a much smaller chance of getting nothing.
So, to get at least 2 pokemon on average each time you need 2/0.1167=17.14... so at least 17.
So, in my opinion, if you have less than 17 pokemon in your deck, quick ball is as useful as dusk Ball.
But of course, that depends on what, in your opinion is the number of pokemon you need to draw, on average, each time, to make Dusk Ball worth more than Quick Ball.
More detailed Mathhammer
really, it should be:
[average number of pokemon drawn] = [No. of Pokemon in deck (not in play, in hand, in discard or in prizes)] * 7/[No. of cards in deck (not in play, in hand, in discard or in prizes)]
But there are so many possibilities there that it would take forever to write them up. You cna do a couple yourselves if you think it'll be useful.
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Daniel Herby- Posts: 34
Join date: 2008-07-06
Re: Quick Ball and Dusk Ball
Combine Dusk ball with say, call energy/roseannes to pull out basics (which most decks do, you'd be a fool to have a deck that can't pull basics) That reduces the chance of getting a pokemon too. (which also makes quick ball more effective.)

Emz- Admin
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